3.40 \(\int \frac{(a g+b g x)^2 (A+B \log (\frac{e (a+b x)}{c+d x}))}{(c i+d i x)^2} \, dx\)

Optimal. Leaf size=260 \[ \frac{2 b B g^2 (b c-a d) \text{PolyLog}\left (2,\frac{d (a+b x)}{b (c+d x)}\right )}{d^3 i^2}+\frac{b g^2 (b c-a d) \log \left (\frac{b c-a d}{b (c+d x)}\right ) \left (2 B \log \left (\frac{e (a+b x)}{c+d x}\right )+2 A+B\right )}{d^3 i^2}+\frac{g^2 (2 A+B) (a+b x) (b c-a d)}{d^2 i^2 (c+d x)}+\frac{g^2 (a+b x)^2 \left (B \log \left (\frac{e (a+b x)}{c+d x}\right )+A\right )}{d i^2 (c+d x)}+\frac{2 B g^2 (a+b x) (b c-a d) \log \left (\frac{e (a+b x)}{c+d x}\right )}{d^2 i^2 (c+d x)}-\frac{2 B g^2 (a+b x) (b c-a d)}{d^2 i^2 (c+d x)} \]

[Out]

(-2*B*(b*c - a*d)*g^2*(a + b*x))/(d^2*i^2*(c + d*x)) + ((2*A + B)*(b*c - a*d)*g^2*(a + b*x))/(d^2*i^2*(c + d*x
)) + (2*B*(b*c - a*d)*g^2*(a + b*x)*Log[(e*(a + b*x))/(c + d*x)])/(d^2*i^2*(c + d*x)) + (g^2*(a + b*x)^2*(A +
B*Log[(e*(a + b*x))/(c + d*x)]))/(d*i^2*(c + d*x)) + (b*(b*c - a*d)*g^2*Log[(b*c - a*d)/(b*(c + d*x))]*(2*A +
B + 2*B*Log[(e*(a + b*x))/(c + d*x)]))/(d^3*i^2) + (2*b*B*(b*c - a*d)*g^2*PolyLog[2, (d*(a + b*x))/(b*(c + d*x
))])/(d^3*i^2)

________________________________________________________________________________________

Rubi [A]  time = 0.532412, antiderivative size = 336, normalized size of antiderivative = 1.29, number of steps used = 18, number of rules used = 13, integrand size = 40, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.325, Rules used = {2528, 2486, 31, 2525, 12, 44, 2524, 2418, 2394, 2393, 2391, 2390, 2301} \[ \frac{2 b B g^2 (b c-a d) \text{PolyLog}\left (2,\frac{b (c+d x)}{b c-a d}\right )}{d^3 i^2}-\frac{g^2 (b c-a d)^2 \left (B \log \left (\frac{e (a+b x)}{c+d x}\right )+A\right )}{d^3 i^2 (c+d x)}-\frac{2 b g^2 (b c-a d) \log (c+d x) \left (B \log \left (\frac{e (a+b x)}{c+d x}\right )+A\right )}{d^3 i^2}+\frac{b B g^2 (a+b x) \log \left (\frac{e (a+b x)}{c+d x}\right )}{d^2 i^2}+\frac{B g^2 (b c-a d)^2}{d^3 i^2 (c+d x)}-\frac{b B g^2 (b c-a d) \log ^2(c+d x)}{d^3 i^2}+\frac{b B g^2 (b c-a d) \log (a+b x)}{d^3 i^2}+\frac{2 b B g^2 (b c-a d) \log (c+d x) \log \left (-\frac{d (a+b x)}{b c-a d}\right )}{d^3 i^2}-\frac{2 b B g^2 (b c-a d) \log (c+d x)}{d^3 i^2}+\frac{A b^2 g^2 x}{d^2 i^2} \]

Antiderivative was successfully verified.

[In]

Int[((a*g + b*g*x)^2*(A + B*Log[(e*(a + b*x))/(c + d*x)]))/(c*i + d*i*x)^2,x]

[Out]

(A*b^2*g^2*x)/(d^2*i^2) + (B*(b*c - a*d)^2*g^2)/(d^3*i^2*(c + d*x)) + (b*B*(b*c - a*d)*g^2*Log[a + b*x])/(d^3*
i^2) + (b*B*g^2*(a + b*x)*Log[(e*(a + b*x))/(c + d*x)])/(d^2*i^2) - ((b*c - a*d)^2*g^2*(A + B*Log[(e*(a + b*x)
)/(c + d*x)]))/(d^3*i^2*(c + d*x)) - (2*b*B*(b*c - a*d)*g^2*Log[c + d*x])/(d^3*i^2) + (2*b*B*(b*c - a*d)*g^2*L
og[-((d*(a + b*x))/(b*c - a*d))]*Log[c + d*x])/(d^3*i^2) - (2*b*(b*c - a*d)*g^2*(A + B*Log[(e*(a + b*x))/(c +
d*x)])*Log[c + d*x])/(d^3*i^2) - (b*B*(b*c - a*d)*g^2*Log[c + d*x]^2)/(d^3*i^2) + (2*b*B*(b*c - a*d)*g^2*PolyL
og[2, (b*(c + d*x))/(b*c - a*d)])/(d^3*i^2)

Rule 2528

Int[((a_.) + Log[(c_.)*(RFx_)^(p_.)]*(b_.))^(n_.)*(RGx_), x_Symbol] :> With[{u = ExpandIntegrand[(a + b*Log[c*
RFx^p])^n, RGx, x]}, Int[u, x] /; SumQ[u]] /; FreeQ[{a, b, c, p}, x] && RationalFunctionQ[RFx, x] && RationalF
unctionQ[RGx, x] && IGtQ[n, 0]

Rule 2486

Int[Log[(e_.)*((f_.)*((a_.) + (b_.)*(x_))^(p_.)*((c_.) + (d_.)*(x_))^(q_.))^(r_.)]^(s_.), x_Symbol] :> Simp[((
a + b*x)*Log[e*(f*(a + b*x)^p*(c + d*x)^q)^r]^s)/b, x] + Dist[(q*r*s*(b*c - a*d))/b, Int[Log[e*(f*(a + b*x)^p*
(c + d*x)^q)^r]^(s - 1)/(c + d*x), x], x] /; FreeQ[{a, b, c, d, e, f, p, q, r, s}, x] && NeQ[b*c - a*d, 0] &&
EqQ[p + q, 0] && IGtQ[s, 0]

Rule 31

Int[((a_) + (b_.)*(x_))^(-1), x_Symbol] :> Simp[Log[RemoveContent[a + b*x, x]]/b, x] /; FreeQ[{a, b}, x]

Rule 2525

Int[((a_.) + Log[(c_.)*(RFx_)^(p_.)]*(b_.))^(n_.)*((d_.) + (e_.)*(x_))^(m_.), x_Symbol] :> Simp[((d + e*x)^(m
+ 1)*(a + b*Log[c*RFx^p])^n)/(e*(m + 1)), x] - Dist[(b*n*p)/(e*(m + 1)), Int[SimplifyIntegrand[((d + e*x)^(m +
1)*(a + b*Log[c*RFx^p])^(n - 1)*D[RFx, x])/RFx, x], x], x] /; FreeQ[{a, b, c, d, e, m, p}, x] && RationalFunc
tionQ[RFx, x] && IGtQ[n, 0] && (EqQ[n, 1] || IntegerQ[m]) && NeQ[m, -1]

Rule 12

Int[(a_)*(u_), x_Symbol] :> Dist[a, Int[u, x], x] /; FreeQ[a, x] &&  !MatchQ[u, (b_)*(v_) /; FreeQ[b, x]]

Rule 44

Int[((a_) + (b_.)*(x_))^(m_.)*((c_.) + (d_.)*(x_))^(n_.), x_Symbol] :> Int[ExpandIntegrand[(a + b*x)^m*(c + d*
x)^n, x], x] /; FreeQ[{a, b, c, d}, x] && NeQ[b*c - a*d, 0] && ILtQ[m, 0] && IntegerQ[n] &&  !(IGtQ[n, 0] && L
tQ[m + n + 2, 0])

Rule 2524

Int[((a_.) + Log[(c_.)*(RFx_)^(p_.)]*(b_.))^(n_.)/((d_.) + (e_.)*(x_)), x_Symbol] :> Simp[(Log[d + e*x]*(a + b
*Log[c*RFx^p])^n)/e, x] - Dist[(b*n*p)/e, Int[(Log[d + e*x]*(a + b*Log[c*RFx^p])^(n - 1)*D[RFx, x])/RFx, x], x
] /; FreeQ[{a, b, c, d, e, p}, x] && RationalFunctionQ[RFx, x] && IGtQ[n, 0]

Rule 2418

Int[((a_.) + Log[(c_.)*((d_) + (e_.)*(x_))^(n_.)]*(b_.))^(p_.)*(RFx_), x_Symbol] :> With[{u = ExpandIntegrand[
(a + b*Log[c*(d + e*x)^n])^p, RFx, x]}, Int[u, x] /; SumQ[u]] /; FreeQ[{a, b, c, d, e, n}, x] && RationalFunct
ionQ[RFx, x] && IntegerQ[p]

Rule 2394

Int[((a_.) + Log[(c_.)*((d_) + (e_.)*(x_))^(n_.)]*(b_.))/((f_.) + (g_.)*(x_)), x_Symbol] :> Simp[(Log[(e*(f +
g*x))/(e*f - d*g)]*(a + b*Log[c*(d + e*x)^n]))/g, x] - Dist[(b*e*n)/g, Int[Log[(e*(f + g*x))/(e*f - d*g)]/(d +
e*x), x], x] /; FreeQ[{a, b, c, d, e, f, g, n}, x] && NeQ[e*f - d*g, 0]

Rule 2393

Int[((a_.) + Log[(c_.)*((d_) + (e_.)*(x_))]*(b_.))/((f_.) + (g_.)*(x_)), x_Symbol] :> Dist[1/g, Subst[Int[(a +
b*Log[1 + (c*e*x)/g])/x, x], x, f + g*x], x] /; FreeQ[{a, b, c, d, e, f, g}, x] && NeQ[e*f - d*g, 0] && EqQ[g
+ c*(e*f - d*g), 0]

Rule 2391

Int[Log[(c_.)*((d_) + (e_.)*(x_)^(n_.))]/(x_), x_Symbol] :> -Simp[PolyLog[2, -(c*e*x^n)]/n, x] /; FreeQ[{c, d,
e, n}, x] && EqQ[c*d, 1]

Rule 2390

Int[((a_.) + Log[(c_.)*((d_) + (e_.)*(x_))^(n_.)]*(b_.))^(p_.)*((f_) + (g_.)*(x_))^(q_.), x_Symbol] :> Dist[1/
e, Subst[Int[((f*x)/d)^q*(a + b*Log[c*x^n])^p, x], x, d + e*x], x] /; FreeQ[{a, b, c, d, e, f, g, n, p, q}, x]
&& EqQ[e*f - d*g, 0]

Rule 2301

Int[((a_.) + Log[(c_.)*(x_)^(n_.)]*(b_.))/(x_), x_Symbol] :> Simp[(a + b*Log[c*x^n])^2/(2*b*n), x] /; FreeQ[{a
, b, c, n}, x]

Rubi steps

\begin{align*} \int \frac{(a g+b g x)^2 \left (A+B \log \left (\frac{e (a+b x)}{c+d x}\right )\right )}{(40 c+40 d x)^2} \, dx &=\int \left (\frac{b^2 g^2 \left (A+B \log \left (\frac{e (a+b x)}{c+d x}\right )\right )}{1600 d^2}+\frac{(-b c+a d)^2 g^2 \left (A+B \log \left (\frac{e (a+b x)}{c+d x}\right )\right )}{1600 d^2 (c+d x)^2}-\frac{b (b c-a d) g^2 \left (A+B \log \left (\frac{e (a+b x)}{c+d x}\right )\right )}{800 d^2 (c+d x)}\right ) \, dx\\ &=\frac{\left (b^2 g^2\right ) \int \left (A+B \log \left (\frac{e (a+b x)}{c+d x}\right )\right ) \, dx}{1600 d^2}-\frac{\left (b (b c-a d) g^2\right ) \int \frac{A+B \log \left (\frac{e (a+b x)}{c+d x}\right )}{c+d x} \, dx}{800 d^2}+\frac{\left ((b c-a d)^2 g^2\right ) \int \frac{A+B \log \left (\frac{e (a+b x)}{c+d x}\right )}{(c+d x)^2} \, dx}{1600 d^2}\\ &=\frac{A b^2 g^2 x}{1600 d^2}-\frac{(b c-a d)^2 g^2 \left (A+B \log \left (\frac{e (a+b x)}{c+d x}\right )\right )}{1600 d^3 (c+d x)}-\frac{b (b c-a d) g^2 \left (A+B \log \left (\frac{e (a+b x)}{c+d x}\right )\right ) \log (c+d x)}{800 d^3}+\frac{\left (b^2 B g^2\right ) \int \log \left (\frac{e (a+b x)}{c+d x}\right ) \, dx}{1600 d^2}+\frac{\left (b B (b c-a d) g^2\right ) \int \frac{(c+d x) \left (-\frac{d e (a+b x)}{(c+d x)^2}+\frac{b e}{c+d x}\right ) \log (c+d x)}{e (a+b x)} \, dx}{800 d^3}+\frac{\left (B (b c-a d)^2 g^2\right ) \int \frac{b c-a d}{(a+b x) (c+d x)^2} \, dx}{1600 d^3}\\ &=\frac{A b^2 g^2 x}{1600 d^2}+\frac{b B g^2 (a+b x) \log \left (\frac{e (a+b x)}{c+d x}\right )}{1600 d^2}-\frac{(b c-a d)^2 g^2 \left (A+B \log \left (\frac{e (a+b x)}{c+d x}\right )\right )}{1600 d^3 (c+d x)}-\frac{b (b c-a d) g^2 \left (A+B \log \left (\frac{e (a+b x)}{c+d x}\right )\right ) \log (c+d x)}{800 d^3}-\frac{\left (b B (b c-a d) g^2\right ) \int \frac{1}{c+d x} \, dx}{1600 d^2}+\frac{\left (B (b c-a d)^3 g^2\right ) \int \frac{1}{(a+b x) (c+d x)^2} \, dx}{1600 d^3}+\frac{\left (b B (b c-a d) g^2\right ) \int \frac{(c+d x) \left (-\frac{d e (a+b x)}{(c+d x)^2}+\frac{b e}{c+d x}\right ) \log (c+d x)}{a+b x} \, dx}{800 d^3 e}\\ &=\frac{A b^2 g^2 x}{1600 d^2}+\frac{b B g^2 (a+b x) \log \left (\frac{e (a+b x)}{c+d x}\right )}{1600 d^2}-\frac{(b c-a d)^2 g^2 \left (A+B \log \left (\frac{e (a+b x)}{c+d x}\right )\right )}{1600 d^3 (c+d x)}-\frac{b B (b c-a d) g^2 \log (c+d x)}{1600 d^3}-\frac{b (b c-a d) g^2 \left (A+B \log \left (\frac{e (a+b x)}{c+d x}\right )\right ) \log (c+d x)}{800 d^3}+\frac{\left (B (b c-a d)^3 g^2\right ) \int \left (\frac{b^2}{(b c-a d)^2 (a+b x)}-\frac{d}{(b c-a d) (c+d x)^2}-\frac{b d}{(b c-a d)^2 (c+d x)}\right ) \, dx}{1600 d^3}+\frac{\left (b B (b c-a d) g^2\right ) \int \left (\frac{b e \log (c+d x)}{a+b x}-\frac{d e \log (c+d x)}{c+d x}\right ) \, dx}{800 d^3 e}\\ &=\frac{A b^2 g^2 x}{1600 d^2}+\frac{B (b c-a d)^2 g^2}{1600 d^3 (c+d x)}+\frac{b B (b c-a d) g^2 \log (a+b x)}{1600 d^3}+\frac{b B g^2 (a+b x) \log \left (\frac{e (a+b x)}{c+d x}\right )}{1600 d^2}-\frac{(b c-a d)^2 g^2 \left (A+B \log \left (\frac{e (a+b x)}{c+d x}\right )\right )}{1600 d^3 (c+d x)}-\frac{b B (b c-a d) g^2 \log (c+d x)}{800 d^3}-\frac{b (b c-a d) g^2 \left (A+B \log \left (\frac{e (a+b x)}{c+d x}\right )\right ) \log (c+d x)}{800 d^3}+\frac{\left (b^2 B (b c-a d) g^2\right ) \int \frac{\log (c+d x)}{a+b x} \, dx}{800 d^3}-\frac{\left (b B (b c-a d) g^2\right ) \int \frac{\log (c+d x)}{c+d x} \, dx}{800 d^2}\\ &=\frac{A b^2 g^2 x}{1600 d^2}+\frac{B (b c-a d)^2 g^2}{1600 d^3 (c+d x)}+\frac{b B (b c-a d) g^2 \log (a+b x)}{1600 d^3}+\frac{b B g^2 (a+b x) \log \left (\frac{e (a+b x)}{c+d x}\right )}{1600 d^2}-\frac{(b c-a d)^2 g^2 \left (A+B \log \left (\frac{e (a+b x)}{c+d x}\right )\right )}{1600 d^3 (c+d x)}-\frac{b B (b c-a d) g^2 \log (c+d x)}{800 d^3}+\frac{b B (b c-a d) g^2 \log \left (-\frac{d (a+b x)}{b c-a d}\right ) \log (c+d x)}{800 d^3}-\frac{b (b c-a d) g^2 \left (A+B \log \left (\frac{e (a+b x)}{c+d x}\right )\right ) \log (c+d x)}{800 d^3}-\frac{\left (b B (b c-a d) g^2\right ) \operatorname{Subst}\left (\int \frac{\log (x)}{x} \, dx,x,c+d x\right )}{800 d^3}-\frac{\left (b B (b c-a d) g^2\right ) \int \frac{\log \left (\frac{d (a+b x)}{-b c+a d}\right )}{c+d x} \, dx}{800 d^2}\\ &=\frac{A b^2 g^2 x}{1600 d^2}+\frac{B (b c-a d)^2 g^2}{1600 d^3 (c+d x)}+\frac{b B (b c-a d) g^2 \log (a+b x)}{1600 d^3}+\frac{b B g^2 (a+b x) \log \left (\frac{e (a+b x)}{c+d x}\right )}{1600 d^2}-\frac{(b c-a d)^2 g^2 \left (A+B \log \left (\frac{e (a+b x)}{c+d x}\right )\right )}{1600 d^3 (c+d x)}-\frac{b B (b c-a d) g^2 \log (c+d x)}{800 d^3}+\frac{b B (b c-a d) g^2 \log \left (-\frac{d (a+b x)}{b c-a d}\right ) \log (c+d x)}{800 d^3}-\frac{b (b c-a d) g^2 \left (A+B \log \left (\frac{e (a+b x)}{c+d x}\right )\right ) \log (c+d x)}{800 d^3}-\frac{b B (b c-a d) g^2 \log ^2(c+d x)}{1600 d^3}-\frac{\left (b B (b c-a d) g^2\right ) \operatorname{Subst}\left (\int \frac{\log \left (1+\frac{b x}{-b c+a d}\right )}{x} \, dx,x,c+d x\right )}{800 d^3}\\ &=\frac{A b^2 g^2 x}{1600 d^2}+\frac{B (b c-a d)^2 g^2}{1600 d^3 (c+d x)}+\frac{b B (b c-a d) g^2 \log (a+b x)}{1600 d^3}+\frac{b B g^2 (a+b x) \log \left (\frac{e (a+b x)}{c+d x}\right )}{1600 d^2}-\frac{(b c-a d)^2 g^2 \left (A+B \log \left (\frac{e (a+b x)}{c+d x}\right )\right )}{1600 d^3 (c+d x)}-\frac{b B (b c-a d) g^2 \log (c+d x)}{800 d^3}+\frac{b B (b c-a d) g^2 \log \left (-\frac{d (a+b x)}{b c-a d}\right ) \log (c+d x)}{800 d^3}-\frac{b (b c-a d) g^2 \left (A+B \log \left (\frac{e (a+b x)}{c+d x}\right )\right ) \log (c+d x)}{800 d^3}-\frac{b B (b c-a d) g^2 \log ^2(c+d x)}{1600 d^3}+\frac{b B (b c-a d) g^2 \text{Li}_2\left (\frac{b (c+d x)}{b c-a d}\right )}{800 d^3}\\ \end{align*}

Mathematica [A]  time = 0.244676, size = 239, normalized size = 0.92 \[ \frac{g^2 \left (b B (b c-a d) \left (2 \text{PolyLog}\left (2,\frac{b (c+d x)}{b c-a d}\right )+\log (c+d x) \left (2 \log \left (\frac{d (a+b x)}{a d-b c}\right )-\log (c+d x)\right )\right )-2 b (b c-a d) \log (c+d x) \left (B \log \left (\frac{e (a+b x)}{c+d x}\right )+A\right )-\frac{(b c-a d)^2 \left (B \log \left (\frac{e (a+b x)}{c+d x}\right )+A\right )}{c+d x}+b B d (a+b x) \log \left (\frac{e (a+b x)}{c+d x}\right )+\frac{B (b c-a d)^2}{c+d x}+b B (b c-a d) \log (a+b x)-2 b B (b c-a d) \log (c+d x)+A b^2 d x\right )}{d^3 i^2} \]

Antiderivative was successfully verified.

[In]

Integrate[((a*g + b*g*x)^2*(A + B*Log[(e*(a + b*x))/(c + d*x)]))/(c*i + d*i*x)^2,x]

[Out]

(g^2*(A*b^2*d*x + (B*(b*c - a*d)^2)/(c + d*x) + b*B*(b*c - a*d)*Log[a + b*x] + b*B*d*(a + b*x)*Log[(e*(a + b*x
))/(c + d*x)] - ((b*c - a*d)^2*(A + B*Log[(e*(a + b*x))/(c + d*x)]))/(c + d*x) - 2*b*B*(b*c - a*d)*Log[c + d*x
] - 2*b*(b*c - a*d)*(A + B*Log[(e*(a + b*x))/(c + d*x)])*Log[c + d*x] + b*B*(b*c - a*d)*((2*Log[(d*(a + b*x))/
(-(b*c) + a*d)] - Log[c + d*x])*Log[c + d*x] + 2*PolyLog[2, (b*(c + d*x))/(b*c - a*d)])))/(d^3*i^2)

________________________________________________________________________________________

Maple [B]  time = 0.171, size = 1382, normalized size = 5.3 \begin{align*} \text{result too large to display} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((b*g*x+a*g)^2*(A+B*ln(e*(b*x+a)/(d*x+c)))/(d*i*x+c*i)^2,x)

[Out]

e/d*g^2/i^2*B*b*ln(b*e/d+(a*d-b*c)*e/d/(d*x+c))/(d*e/(d*x+c)*a-e/(d*x+c)*b*c)/(d*x+c)*a^2+2/d^2*g^2/i^2*B*ln(b
*e/d+(a*d-b*c)*e/d/(d*x+c))/(d*x+c)*a*b*c-1/d*g^2/i^2*A/(d*x+c)*a^2+1/d*g^2/i^2*B/(d*x+c)*a^2+e/d^3*g^2/i^2*B*
b^3*ln(b*e/d+(a*d-b*c)*e/d/(d*x+c))/(d*e/(d*x+c)*a-e/(d*x+c)*b*c)/(d*x+c)*c^2+2/d^3*g^2/i^2*B*b^2*ln(b*e/d+(a*
d-b*c)*e/d/(d*x+c))*ln(-(d*(b*e/d+(a*d-b*c)*e/d/(d*x+c))-b*e)/b/e)*c-1/d^3*g^2/i^2*B*ln(b*e/d+(a*d-b*c)*e/d/(d
*x+c))/(d*x+c)*b^2*c^2-2/d^2*g^2/i^2*B*b*ln(b*e/d+(a*d-b*c)*e/d/(d*x+c))*ln(-(d*(b*e/d+(a*d-b*c)*e/d/(d*x+c))-
b*e)/b/e)*a+e/d^2*g^2/i^2*A*b^2/(d*e/(d*x+c)*a-e/(d*x+c)*b*c)*a-e/d^3*g^2/i^2*A*b^3/(d*e/(d*x+c)*a-e/(d*x+c)*b
*c)*c+2/d^2*g^2/i^2*A/(d*x+c)*a*b*c-2/d^2*g^2/i^2*B/(d*x+c)*a*b*c-2*e/d^2*g^2/i^2*B*b^2*ln(b*e/d+(a*d-b*c)*e/d
/(d*x+c))/(d*e/(d*x+c)*a-e/(d*x+c)*b*c)/(d*x+c)*a*c-e/d^3*g^2/i^2*B*b^3*ln(b*e/d+(a*d-b*c)*e/d/(d*x+c))/(d*e/(
d*x+c)*a-e/(d*x+c)*b*c)*c+e/d^2*g^2/i^2*B*b^2*ln(b*e/d+(a*d-b*c)*e/d/(d*x+c))/(d*e/(d*x+c)*a-e/(d*x+c)*b*c)*a+
1/d^3*g^2/i^2*B/(d*x+c)*b^2*c^2-1/d^2*g^2/i^2*A*b*a+1/d^3*g^2/i^2*A*b^2*c+1/d^2*g^2/i^2*B*b*a-1/d^3*g^2/i^2*B*
b^2*c+1/d^3*g^2/i^2*B*ln(b*e/d+(a*d-b*c)*e/d/(d*x+c))*b^2*c-1/d^3*g^2/i^2*A/(d*x+c)*b^2*c^2+2/d^3*g^2/i^2*A*b^
2*ln(d*(b*e/d+(a*d-b*c)*e/d/(d*x+c))-b*e)*c-2/d^2*g^2/i^2*A*b*ln(d*(b*e/d+(a*d-b*c)*e/d/(d*x+c))-b*e)*a-1/d^2*
g^2/i^2*B*b*ln(d*(b*e/d+(a*d-b*c)*e/d/(d*x+c))-b*e)*a+1/d^3*g^2/i^2*B*b^2*ln(d*(b*e/d+(a*d-b*c)*e/d/(d*x+c))-b
*e)*c+2/d^3*g^2/i^2*B*b^2*dilog(-(d*(b*e/d+(a*d-b*c)*e/d/(d*x+c))-b*e)/b/e)*c-1/d*g^2/i^2*B*ln(b*e/d+(a*d-b*c)
*e/d/(d*x+c))/(d*x+c)*a^2-1/d^2*g^2/i^2*B*ln(b*e/d+(a*d-b*c)*e/d/(d*x+c))*b*a-2/d^2*g^2/i^2*B*b*dilog(-(d*(b*e
/d+(a*d-b*c)*e/d/(d*x+c))-b*e)/b/e)*a

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Maxima [B]  time = 1.53016, size = 1196, normalized size = 4.6 \begin{align*} \text{result too large to display} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*g*x+a*g)^2*(A+B*log(e*(b*x+a)/(d*x+c)))/(d*i*x+c*i)^2,x, algorithm="maxima")

[Out]

-A*b^2*(c^2/(d^4*i^2*x + c*d^3*i^2) - x/(d^2*i^2) + 2*c*log(d*x + c)/(d^3*i^2))*g^2 + 2*A*a*b*g^2*(c/(d^3*i^2*
x + c*d^2*i^2) + log(d*x + c)/(d^2*i^2)) - B*a^2*g^2*(log(b*e*x/(d*x + c) + a*e/(d*x + c))/(d^2*i^2*x + c*d*i^
2) - 1/(d^2*i^2*x + c*d*i^2) - b*log(b*x + a)/((b*c*d - a*d^2)*i^2) + b*log(d*x + c)/((b*c*d - a*d^2)*i^2)) -
A*a^2*g^2/(d^2*i^2*x + c*d*i^2) - (2*a^2*b*d^2*g^2*log(e) + 2*(g^2*log(e) + g^2)*b^3*c^2 - (4*g^2*log(e) + 3*g
^2)*a*b^2*c*d)*B*log(d*x + c)/(b*c*d^3*i^2 - a*d^4*i^2) + ((b^3*c*d^2*g^2*log(e) - a*b^2*d^3*g^2*log(e))*B*x^2
+ (b^3*c^2*d*g^2*log(e) - a*b^2*c*d^2*g^2*log(e))*B*x + ((b^3*c^2*d*g^2 - 2*a*b^2*c*d^2*g^2 + a^2*b*d^3*g^2)*
B*x + (b^3*c^3*g^2 - 2*a*b^2*c^2*d*g^2 + a^2*b*c*d^2*g^2)*B)*log(d*x + c)^2 - ((g^2*log(e) - g^2)*b^3*c^3 - 3*
(g^2*log(e) - g^2)*a*b^2*c^2*d + 2*(g^2*log(e) - g^2)*a^2*b*c*d^2)*B + ((b^3*c*d^2*g^2 - a*b^2*d^3*g^2)*B*x^2
+ (2*b^3*c^2*d*g^2 - 2*a*b^2*c*d^2*g^2 - a^2*b*d^3*g^2)*B*x + (2*a*b^2*c^2*d*g^2 - 3*a^2*b*c*d^2*g^2)*B)*log(b
*x + a) - ((b^3*c*d^2*g^2 - a*b^2*d^3*g^2)*B*x^2 + (b^3*c^2*d*g^2 - a*b^2*c*d^2*g^2)*B*x - (b^3*c^3*g^2 - 3*a*
b^2*c^2*d*g^2 + 2*a^2*b*c*d^2*g^2)*B)*log(d*x + c))/(b*c^2*d^3*i^2 - a*c*d^4*i^2 + (b*c*d^4*i^2 - a*d^5*i^2)*x
) - 2*(b^2*c*g^2 - a*b*d*g^2)*(log(b*x + a)*log((b*d*x + a*d)/(b*c - a*d) + 1) + dilog(-(b*d*x + a*d)/(b*c - a
*d)))*B/(d^3*i^2)

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Fricas [F]  time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{A b^{2} g^{2} x^{2} + 2 \, A a b g^{2} x + A a^{2} g^{2} +{\left (B b^{2} g^{2} x^{2} + 2 \, B a b g^{2} x + B a^{2} g^{2}\right )} \log \left (\frac{b e x + a e}{d x + c}\right )}{d^{2} i^{2} x^{2} + 2 \, c d i^{2} x + c^{2} i^{2}}, x\right ) \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*g*x+a*g)^2*(A+B*log(e*(b*x+a)/(d*x+c)))/(d*i*x+c*i)^2,x, algorithm="fricas")

[Out]

integral((A*b^2*g^2*x^2 + 2*A*a*b*g^2*x + A*a^2*g^2 + (B*b^2*g^2*x^2 + 2*B*a*b*g^2*x + B*a^2*g^2)*log((b*e*x +
a*e)/(d*x + c)))/(d^2*i^2*x^2 + 2*c*d*i^2*x + c^2*i^2), x)

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Sympy [F(-1)]  time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*g*x+a*g)**2*(A+B*ln(e*(b*x+a)/(d*x+c)))/(d*i*x+c*i)**2,x)

[Out]

Timed out

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Giac [F]  time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (b g x + a g\right )}^{2}{\left (B \log \left (\frac{{\left (b x + a\right )} e}{d x + c}\right ) + A\right )}}{{\left (d i x + c i\right )}^{2}}\,{d x} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*g*x+a*g)^2*(A+B*log(e*(b*x+a)/(d*x+c)))/(d*i*x+c*i)^2,x, algorithm="giac")

[Out]

integrate((b*g*x + a*g)^2*(B*log((b*x + a)*e/(d*x + c)) + A)/(d*i*x + c*i)^2, x)